**POSITION 5.**

**This outer-marker sits 105.6-feet from the hubstone at a return angle back to the hubstone of 22.5-degrees.**

**Whereas the previous position (4) gave a tutorial based upon 105-feet and its relationship to navigating by the 5250-feet mile, this position (5) introduces 105.6-feet and navigation by the mile of 5280-feet. **

**Note:** 10500-feet is 2 Greek miles of 5250-feet each, whereas 10560-feet is 2 English miles of 5280-feet each. On megalithic or mound complex sites across the world it’s a general rule of thumb that whenever the mile of 5250-feet is encoded, very close by the mile of 5280-feet will also be encoded simultaneously.

**POSITION 6.**

** **

The very learned, ancient ** Masters of the Craft,** teaching initiate students on this

**The large obelisk and its smaller companion appear to have been tumbled towards the west from their former standing positions. Given their individual girths, they undoubtedly contained a whole raft of numerically close-proximity distance and angle codes.**

The smaller of the two complies well to coding a distance of 68.75-feet from the hubstone, with a second reading of 69.12-feet. The angle dissecting the boulder would be 200-degrees, with a return angle of 20-degrees. The return angle could also be read as 20.16-degrees and a tutorial about the merits of 2016 (1/3rd of 1-minute of arc) could also be discussed.

The value **69.12-miles** (of 5250-feet) was 1-degree of equatorial arc under the Great Pyramid’s literal geodetic system of navigation, with 1-minute of arc set at 6048-feet. This was the “6&7” system where the distance increments were divisible by either 6 or 7. For example, the 5250-feet mile = 750 X 7 or 875 X 6.

The value** 68.75-miles** (of 5280-feet) was 1-degree of equatorial arc under the slightly elongated system that set 1-minute of arc at 6050-feet. This was the “11” system, where all distance increments were divisible by “11”. For example, the 5280-feet mile = 480 X 11.

Alternatively, across the wide girth of the big obelisk a much larger selection of distance codes, extractible by a calibrated measuring rope or string, could be identified. These include:

**64.8- feet** (Precession of the Equinoxes). In the duration of Precession (25920-years), 6480-years would be 1/4th of the cycle.

**65.34-feet** (The equatorial circumference under the 5280-feet mile system). Under that system, with 6050-feet being 1-minute of arc, the total number of feet circumnavigating the world equated to 130680000-feet or 65340000 X 2.

**66-feet** (1-chain or 1/80th of the 5280-feet mile … or 1/90th of the 5940-feet Scottish mile).

**67.2-feet** (navigational coding made up of 1/90th divisions of 1-minute of equatorial arc). 67.2 X 90 = 6048.

**68.04-feet** (Lunar nutation cycle of 6804-days duration).

Over the girth of the obelisk, 3 close proximity Egyptian Royal Cubits values could be accommodated by way of the degree angle… ranging in a marginal sweep from **206.18 to 206.25 to 207.36 –degrees **respectively.

The first of the Egyptian Royal Cubits, here under consideration (and found in the Turin Museum) was 20.61818182-inches. Its exact length is determined by taking the base length of the Great Pyramid and dividing by 440. Therefore, 756-feet (9072-inches) ÷ 440 = 20.61818182-inches.

The Royal Cubit, with its irregular segment divisions, was not used for construction, but only as a mnemonic device for remembering the equatorial size of the Earth. The key was to read the full-length inch value of the cubit as miles of 5280-feet, then multiply the cubit’s length by 1200.

Therefore: 20.61818182-miles X 1200 = 24741.818181818181-miles, which converts to 130636800-feet or 12 X 12 X 12 X 12 X 1.2 Greek miles of 5250-feet each (24883.2 Greek miles) or 6048-feet per minute of arc.

The second Royal Cubit, found by Petrie was 20.625-inches. Its exact length is determined by taking the slightly elongated base length of the Great Pyramid (756.25-feet) and dividing by 440. The sum of 756.25-feet (9075-inches) ÷ 440 = 20.625-inches.

Therefore: 20.625-miles X 1200 = 24750-miles of 5280-feet each. This converts to 130680000-feet or 6050-feet per minute of arc.

The third Royal Cubit was found by measuring the Great Pyramid’s paving slabs as 1.728-feet or 20.736-inches.

Therefore 20.736-miles of 5280-feet each X 1200 = 24883.2-miles or 131383296-feet or 6082.56-feet per minute of arc. The true equatorial circumference (24902-miles) is 131482560-feet or 6087.15-feet per minute of arc, but this value is not fluidly divisible or factorable down into smaller whole numbers and easily calculated fractions for navigational determinations.

**POSITION 7.**

**This position is made up of 1 sizable boulder and a hefty obelisk. Over its expanse several coded readings are possible onto the two component stones, including 105.6-feet @ 165-degrees onto the large obelisk (background); also a distance of 101.25-feet or 105-feet, at a return angle of 343.75-degrees more centrally, The foreground boulder complies with a coded distance of 105-feet on an angle of 157.5-degrees. **

**The two component parts, side-by-side, of position 7.**

1. The first reading of 105.6-feet @ 165-degrees relates to navigation under the mile of 5280-feet and league of 16500-feet (3.125-miles).

A reading of 101.25-feet encodes the following progression:

101.25, 202.5, 303.75, 405, 506.25, 607.5, **708.75**, 810, 911.25, 1012.5, 1113.75, 1215, … 1620, … 2430, … 2531.25, … **2835**, … 3543.75, … etc.

In the lunar-year of 354.375-days, there would be 35 X 10.125-days (243-hours). Also, in the 6804-day duration of the lunar nutation cycle there would be 19.2 lunar years or 672 intervals of 10.125-days.

It must be remembered that without the luxury of perishable books the duration and breakdown of lunar cycles had to be ** memorised** in factorable number strings in order to stay daily abreast of progress within the lunisolar calendar.

In the above string the value **708.75** (in feet) is the design length of the Khafre Pyramid of Egypt and **2835-feet** is the distance around the pyramid for all 4 sides.

2. A reading of 105-feet would, of course, be 10 reeds of 10.5-feet each (126-inches or 10 Greek feet).

3. A return angle of 343.75-degrees is navigational coding under the 5280-mile navigational system and a progression derived from this value goes:

343.75, **687.5**, 1031.25, 1375, 1718.75, **2062.5**, 2406.25, 2750, … **5156.25**, … 5500, … 6187.5, … 6875, … **7562.5**, … 8250, … 11000, … **16500**, … **24750**.

In the above line-up, 68.75-miles of 5280-feet would be 1-degree of equatorial arc; 20.625-inches would be a Royal Egyptian cubit used for mnemonic reference to the 24750-mile equatorial circumference; 756.25-feet would be the symbolic length of the Great Pyramid in order to create the “11” navigational system, with a mile of 5280-feet and 6050-feet being 1-minute of equatorial arc; 16500-feet is, of course, 1-English league and 24750-miles is the equatorial circumference by this method of grid-referencing the world for navigation.

4. Moving our attention to the smaller boulder, the length is coded to be 105-feet (100 Greek feet) and the angle is 157.5-degrees.

The sum of 157.5-feet would be 1/4th of a Greek stadia (stadium) of 630-feet.

**POSITION 8.**

** **

**The apparent codes for this small boulder are 141.75-feet from the hubstone @ 155.52-degrees.**

**The reasonably small boulder outer-marker.**

The distance code of 141.75-feet initiates the following progression:

**141.75, 283.5**, 425.25, 567, **708.75**, 850.5, 992.25, 1134, 1275.75, 1417.5, … **1701**, … 2268, … **2551.5**, … 2835, … **3402**, … **3543.75**, … **4536**, … **6804**, … **9072**, … etc.

This progression is both lunar and navigational coding.

1. A period of 141.75-days (**3402-hours**) would be 1/48th of the **6804-day** lunar nutation cycle. In this line-up are the values for side and full circumnavigation lengths of the Khafre Pyramid (Egypt’s pyramid of the moon) …708.75-feet per side and 2835-feet around.

2. The ¼, ½, ¾, and full periods of the 6804-day lunar cycle are present in the progression.

3. Under the lunisolar Sabbatical Calendar system, both the sun and the moon were tracked on a daily basis for 7-solar years and 7.2 lunar years concurrently. Once the solar count was commenced on the summer solstice the druids would wait 6-days (5.25-actual) then begin the lunar count, in conjunction with the mistletoe culling ceremony (cutting sprigs of parasitic mistletoe vines away from an oak tree it had entwined). For this a golden sickle was used (gold representing the sun & the crescent shape representing the waning moon). Below the tree other druids danced around the tree singing ** “Hey-Derry-Derry-Down”**.

Under the Sabbatical Calendar count thus initiated, the solar count of days ran for 2556.75-days (7-solar years) whereas the lunar count ran for **2551.5-days** (7.2 lunar years), with both periods ending on the same day.

4. Again we have the lunar year value mentioned, as well as **453.6** (the vertical height of the Great Pyramid to its top floor altar). It was designed as a truncated pyramid without a capstone. There is also 9072, the length of the Great Pyramid in inches or (in feet) 1.5 –minutes of equatorial arc @ 6048-feet per minute. Note: 9072 ÷ 2 = 4536.

5. The degree angle is 155.52 and this value relates to the equatorial circumference of the Earth configured to be 24883.2-miles around.

A progression based upon 155.52 goes:

**155.52**, **311.04**, 466.56, 622.08, 777.6, **933.12**, 1088.64, **1244.16**, … 1555.2, … 1866.24, … **24883.2.**

The sum of 1555.2-miles would be 1/16th of the equatorial circumference or 22.5-degrees of arc; 3110.4-miles would be 45-degrees; 12441.6-miles would be half the circumference.

6. These overall values in the progressions of the ancient mathematicians were encoded into all ** weights, measures & volumes standards** of the cousin civilisations and the value